Technical Details. Basically : DocumentBuilder db = ...; String xml = ...; db.parse (new InputSource (new StringReader (xml))); Note that if you read your XML from a file, you can directly give the File object to DocumentBuilder.parse () . Xml - Front-end - GUJ Sr.No Method & description; 1: disconnect() This method releases this connection so that its resources may be either reused or closed. Protocol Error: java.net.MalformedURLException: no protocol: - SAP Specifying a handler of null indicates that the URL should use a default stream handler for the protocol, as outlined for: java.net.URL#URL(java.lang.String, java.lang.String, int, java.lang.String) Copy link Member fvanderbiest commented Feb … 使用Http协议异常：java.net.MalformedURLException: no protocol: … If the url you have passed in the string which cannot be parsed or, without legal protocol a MalformedURLException is generated. In the following Java example we are tring to get establish a connection to a page and publishing the response. bug priority-top. Assignees No one assigned Labels None yet Projects None yet Milestone No milestone Linked pull requests … Change all / to \ in the … java.net.MalformedURLException: no protocol java Sr.No. Exception : java.net.MalformedURLException: no protocol while reading json via POSTMAN. Ich habe versucht, die URL zu einem HTTP-Link anstelle von HTTPS zu machen (in dem Gedanken, dass "kein Protokoll" bedeutet, dass mein lokaler Java-Client aus dem einen oder anderen Grund keine HTTPS-URL erreichen kann) . 今天在用JAVA读取XML数据时出现的在这个异常，java.net.MalformedURLException: no protocol 初次判断是编码问题，然后上网搜了一下找到解决的办法。 我的代码是 DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance(); DocumentBuild Image Error : java.net.MalformedURLException: no protocol